#Monkey考研英语[超话]#
打卡第48天
✓grant v.赋予,授予(权利)n.[拨款(财政]
✓the Revolutionary War n.美国独立战争
✓Cilvil war n.美国南北战争
✓aftermath n.(不好的后果)(补第47天)
————————————————————
✓performance n.表现,性能,业绩~do
✓it may be said…可能有人说…/可能有这种说法…
✓social institution 公立学校
✓motive n.动机
打卡第48天
✓grant v.赋予,授予(权利)n.[拨款(财政]
✓the Revolutionary War n.美国独立战争
✓Cilvil war n.美国南北战争
✓aftermath n.(不好的后果)(补第47天)
————————————————————
✓performance n.表现,性能,业绩~do
✓it may be said…可能有人说…/可能有这种说法…
✓social institution 公立学校
✓motive n.动机
L12-3 阅读 Why Do You Need A Vocabulary
● salary: n. 薪水
● allowance: n. 津贴,零花钱
Uncle Bear never gives his daughter any allowance.
● own: v. 拥有
Key sentences: 关键句型
#宝宝的少女心#
1. I don't have time to work…
have time for something/to do something… 有时间做某事
◆ Uncle Bear doesn't have time for movies.
◆ Uncle Bear doesn't have time to see a movie.
2. I take care of the baby.
take care of: 照看,也可以说look after
◆ Uncle Bear doesn't take care of his daughter.
◆ Uncle Bear doesn't look after his daughter.
3. I don't get an allowance from my parents anymore.
not … anymore: 再也不…
◆ Uncle Bear doesn't teach English anymore.
◆ Helen doesn't eat pork anymore.
Uncle Bear owns a big house Job
● salary: n. 薪水
● allowance: n. 津贴,零花钱
Uncle Bear never gives his daughter any allowance.
● own: v. 拥有
Key sentences: 关键句型
#宝宝的少女心#
1. I don't have time to work…
have time for something/to do something… 有时间做某事
◆ Uncle Bear doesn't have time for movies.
◆ Uncle Bear doesn't have time to see a movie.
2. I take care of the baby.
take care of: 照看,也可以说look after
◆ Uncle Bear doesn't take care of his daughter.
◆ Uncle Bear doesn't look after his daughter.
3. I don't get an allowance from my parents anymore.
not … anymore: 再也不…
◆ Uncle Bear doesn't teach English anymore.
◆ Helen doesn't eat pork anymore.
Uncle Bear owns a big house Job
C语言-switch语句执行顺序
#c语言#
①例子
#include< stdio.h>
main()
{int k=5,n=0;
do {
switch(k){
case1:case3:n+=1;k--;break;
/*当k=1或3时,执行此句,这是两种case合并成一行了。*/
default:n=0;k--;
/*当k不等于1234时,执行此句,默认兜底情况。*/
case2:case4:n+=2;k--;break;}
/*当k=2或4时,执行此句。*/
printf("%d",n);
}
while(k>0&&n<5);
/*此句已经不属于switch语句,
只要满足循环条件k>0且n<5,就继续将k值输入switch 语句,
直到条件不满足,循环结束,输出结束。*/
}
~
②执行顺序
该程序存在嵌套语句,
外层为do{}while()语句,
内层为switch语句和printf语句。
switch语句中有3行3种情况,
根据k值找到对应case标号,
没有对应case执行默认default情况,
注意:
对应 case或default之后的情况也要执行,直到 switch语句结束。
除非遇到 break,才能提前结束switch语句。
~
③计算过程
第一次循环
初值:k==5,n==0
(1)switch语句
没有对应case
执行default: n==0,k==4
执行case2:case4:n==2,k==3
break跳出 switch语句
(2)printf语句
打印 n==2
~
第二次循环
k==3,n==2
(1)switch语句
对应case3
执行case1:case3:n==3,k==2
break跳出 switch语句
(2)printf语句
打印 n==3
~
第三次循环
k==2,n==3
(1)switch语句
对应case2
执行case2:case4:n==5,k==1
break跳出 switch语句
(2)printf语句
打印 n==5
~
此时n不满足循环条件k>0&&n<5
跳出整个do()while()循环
最终打印结果:235
#c语言#
①例子
#include< stdio.h>
main()
{int k=5,n=0;
do {
switch(k){
case1:case3:n+=1;k--;break;
/*当k=1或3时,执行此句,这是两种case合并成一行了。*/
default:n=0;k--;
/*当k不等于1234时,执行此句,默认兜底情况。*/
case2:case4:n+=2;k--;break;}
/*当k=2或4时,执行此句。*/
printf("%d",n);
}
while(k>0&&n<5);
/*此句已经不属于switch语句,
只要满足循环条件k>0且n<5,就继续将k值输入switch 语句,
直到条件不满足,循环结束,输出结束。*/
}
~
②执行顺序
该程序存在嵌套语句,
外层为do{}while()语句,
内层为switch语句和printf语句。
switch语句中有3行3种情况,
根据k值找到对应case标号,
没有对应case执行默认default情况,
注意:
对应 case或default之后的情况也要执行,直到 switch语句结束。
除非遇到 break,才能提前结束switch语句。
~
③计算过程
第一次循环
初值:k==5,n==0
(1)switch语句
没有对应case
执行default: n==0,k==4
执行case2:case4:n==2,k==3
break跳出 switch语句
(2)printf语句
打印 n==2
~
第二次循环
k==3,n==2
(1)switch语句
对应case3
执行case1:case3:n==3,k==2
break跳出 switch语句
(2)printf语句
打印 n==3
~
第三次循环
k==2,n==3
(1)switch语句
对应case2
执行case2:case4:n==5,k==1
break跳出 switch语句
(2)printf语句
打印 n==5
~
此时n不满足循环条件k>0&&n<5
跳出整个do()while()循环
最终打印结果:235
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